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External System Bus Architecture :
This is a 16 bit processor with 40 pins. It has twenty address pins and out of which sixteen are utilized as data pins. This concept of by using similar pins for data andaddress both is called Multiplexing. lt has 16 signals. It may access a memory of 1 MB.(220).
It has 14 registers which are 16 bits wide. There are a set of arithmetic registers, set of pointers (Base and Index registers), set of segment registers. It has Flag register or program status word (PSW) and a instruction pointer.
Instruction queue: It may queue 6 bytes at a time.
calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction
how we can multiply two 8 bit number with rotation
This unit introduces the topic of evaluating interactive products. It is a short unit as evaluation is discussed in more detail in Block 4. Its brevity should give you additional t
Trying to convert small programs from C to 8086 assembly language using emu 8086 emulator. I converted to low level C, but struggling with converting to the Assembly language.
SHL/SAL : Shift logical/Arithmetic Left: These instructions shift the operand byte or word bit by bit to the left and insert 0 in the newly introduced least significant bits. In c
DMA Hardware (8237 DMAC) : 1)Processor contain HOLD/HOLD Acknowledge lines to interact with 8237 o DMAC can achieve control of ISA bus by asserting HOLD o P
MLIL: Unsigned Multiplication Byte or Word: This instruction multiplies an unsigned byte or word by the contents of the AL. The unsigned byte or word can be in any one of the gene
Typical link to modems for synchronous and asynchronous transmissions are shown in Figure. With regard to the synchronous connections it is consider that the timing is controlled
Interrupt Priority Management The interrupt priority management logic indicated in given figure can be implemented in several ways. It does not required to be present in system
As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests
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