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Uniform Alternate Electric Field
Suppose a particle moves under a uniform (i.e. independent of space co-ordinates) but alternating electric field E given by,
E = E0 sin ω t = ( E0 i) sin ω t (i)where, E0 is amplitude and ω is angular frequency of oscillation. We define the direction of electric field as X-axis.The equation of motion of the particle of mass m and charge q in this field is, Integrating, we find where constant of integration c1 is set by initial condition: at t = 0, when E = 0, let v = v0. Hence, we get Integrating once again, we find where constant of integration r0 is the initial position of the particle; at t = 0, r = r0.We can always put r0 = 0; let us also take v0 = 0. Further, if E0 = E0 i, we have The particle moves along X-axis with time dependent speed vx (t). The average speed of the particle during a cycle is, vx is called the drift velocity of the particle. The displacement of the particle during one complete cycle, i.e. in time T, The graph between x and t is obtained by superposing the sine curve and the straight line,x = x1 + x2 If v0 ≠ 0, the particle may continue to move along y and z directions with constant initial velocities voy and voz. Simultaneously, it is drifted towards X-axis by a fixed distance per cycle, viz.
SPOT WELDING In this type of welding, after proper cleaning of the surfaces, the metals to be welded are kept one above the other and two copper electrodes are kept on both sid
can you help me to do my project on machine design,it is specific project with calculation and some draw.
Two identical rollers, each of weight W= 1000N are placed by an inclined plane and a vertical wall as shown below. Determine the reactions at the points of supports A, B, and C. Su
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Calculation of Material Removal Rate MRR = (W i - W f ) × 1000/ 7.8 × T .......................................... (1) W i = Initial weight of work piece W f = Final w
Determine the concurrent forces: Four coplanar concurrent forces act at point and keep it at rest. These are mention in Figure. Determine the forces P and Q. Solution
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