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Types of Light Resources - illumination Model
Let us discuss about the types of light resources. The light sources can not merely be natural like light from Sun or Moon or Stars although this could be man-made devices as like tube or bulb and so no, or a highly polished surface. The light resources are considered as Luminous objects that are the objects which emit radiant energy and they can be of both kinds light emitting source that could be of any form point/diffuse or distributed objects emitting radiant energy) and a light reflecting source as Reflecting surfaces are occasionally considered to as light reflecting sources, which is any polished surface able of reflecting, a referred amount of light rays.
Q. What is Monitor? A Monitor is a television like box connected to your computer and providing you a vision into the mind of your PC. It displays what your computer is thinki
Linearly interpolate - Modeling and Rendering I 4 = I 1 + t (I 2 - I 1 ); here t = (|y 1 - y 2 |)/(|y 1 - y 2 |) I D = I A + t (I B - I A ); here t = (|AD|)/(|AB|)
Implement displacement mapping and bump mapping on a sphere. The displacement can be whatever your choice. The bump map can be whatever your choice as well.
LCD - Liquid Crystal Display A liquid crystal display consists of two glass plates each containing a light polarizer. One glass plate contains vertical polarizer and the ot
Question 1: (a) How can you select and manipulate individual objects in a group? (b) How do you resize an object? Explain how you determine the point from which the object r
For this assignment, you will program a game called Pig. Pig is a two-player game where players compete to be the first to reach (or surpass) 100 points. Pig usually involves playe
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List out the merits and demerits of DVST? The merits and demerits of direct view storage tubes [DVST] are as follows It has a flat screen Refreshing of screen is
Transformation for 3-D Reflection For 3-Dimensions reflections, we should to know the reference plane, which is a plane about that reflection is to be considered. Remember tha
To prove ‾P (1) = p n Solution : since in the above case we determine each term excluding B n,n (u) will have numerous of (1 - u) i (i = 0 to n) consequently by using u = 1
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