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One might assume that non-closure under concatenation would imply non closure under both Kleene- and positive closure, since the concatenation of a language with itself is included
a) Let n be the pumping lemma constant. Then if L is regular, PL implies that s can be decomposed into xyz, |y| > 0, |xy| ≤n, such that xy i z is in L for all i ≥0. Since the le
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how to write program Minimum Cost Calculation - Vogel Approximation Method(VAM
The key thing about the Suffx Substitution Closure property is that it does not make any explicit reference to the automaton that recognizes the language. While the argument tha
a finite automata accepting strings over {a,b} ending in abbbba
Give the Myhill graph of your automaton. (You may use a single node to represent the entire set of symbols of the English alphabet, another to represent the entire set of decima
proof ogdens lemma .with example i am not able to undestand the meaning of distinguished position .
State & prove pumping lemma for regular set. Show that for the language L={ap |p is a prime} is not regular
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