Illustrate classification of matter, Chemistry

Assignment Help:

Q. Illustrate Classification of Matter?

Pure Substances

In order to understand what a pure substance is, you must think of it on an atomic level.

Elements and compounds are pure substances. An element is a substance that is made up of only one type of atom. Gold, iron, and chlorine are examples of elements. Currently, there are 112 known elements. Of these, 88 occur in nature and are found in abundance on Earth, and the remaining elements can be synthesized in the laboratory by means of nuclear reactions.

Consider this caterpillar a molecule of an element. Although there are many segments, each part is the same. If we had a lot of these caterpillars put together, there would still be only one type of segment present. That makes it an element.

In contrast to an element, a compound is a pure substance that is composed of different types of atoms. In other words, compounds are composed of two or more different elements. The different atoms in a compound combine in specific ratios. The atoms from the individual elements loose their identities when forming the compound. In other words, a compound has properties different from the elements that comprise it.

Mixtures

A mixture is a combination of two or more substances. Unlike the elements of a compound, the individual components of a mixture retain their identities. A mixture can be described as bring either homogeneous or heterogeneous.

A homogeneous mixture has uniform composition throughout the mixture. A homogeneous mixture is also called a solution. A solution contains a mixture of two or more substances which cannot easily be distinguished from one another. For example, when you create a solution by dissolving sugar in water, it is difficult to distinguish the sugar molecules from the water molecules.


Related Discussions:- Illustrate classification of matter

Explain reaction for benzyl chloride to benzyl alcohol, How are the followi...

How are the following conversions carried out? (i)  Benzyl chloride to benzyl alcohol, (ii)  Methyl magnesium bromide to 2- methlpropan -2-ol,

Solution, How we get 49 gm = 1 eqv

How we get 49 gm = 1 eqv

Iodometric titrations and iodimetric, Iodometric Titrations and Iodimetric ...

Iodometric Titrations and Iodimetric The reduction of free iodine to iodide ions and oxidation of iodide ions to free iodine takes place in these titrations. I 2 + 2e - →

How to evaluate mass number, Q. How to evaluate mass number? An isotope...

Q. How to evaluate mass number? An isotope of an element is recognized by its mass number which is the sum of the number of protons and neutrons in the atom's nucleus. Mas

Define functional food, Q. Define functional food? Functional food is a...

Q. Define functional food? Functional food is a food that has a component incorporated into it to give a specific medical or physiological benefit, other than a purely nutritio

Bohr''s model of the hydrogen atom, Which of the following statements does ...

Which of the following statements does not form part of Bohr's model of the hydrogen atom: (1) Energy of the electrons in the orbit is quantized (2) The electron in the orbi

Highest melting point, Highest melting point would be of: (1) He       ...

Highest melting point would be of: (1) He        (2) CsCl      (3)  NH 3   (4)  CHCl 3 Ans:  CsCl

Expansion work, write the expression for the expansion work?

write the expression for the expansion work?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd