Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Illustrate Born-Haber cycle?
Boron is always covalent and does not form,B3+ ions, because' the energy required to remove three electrons is very high. Many simple compounds of A1 and Ga like AlCl3 and GaCl3 are also covalent when anhydrous. However, in solution, the large amount of hydration energy evolved compensates the high ionisation energy and all the' metal ions exist in a hydrated state.
This can be explained with the help of Born-Haber cycle as given below. However, this is a simplified approach given only on the bas; of enthalpy changes, whereas the direction and extent of any reaction depend on the free energy changes which take into account changes both in enthalpy and entropy.
Thus, despite the large ionisation energies of aluminium, the enthalpy of' solution of AlCl3 has a large negative value. Therefore, in aqueous solution, AIC3 exists as AI3+(aq) and Cl-(aq). It might be thought that the same argument would apply to BCI3; But to make the enthalpy of solution of BCl3 nethalpy the enthalpy of hydration of B3+ should be - 6009 KJ which is unlikely for the small B3+cation. Therefore, BC13 hydrolyses in aqueous solution to give boric acid and not B3+ (aq).
BCl3 + 3H20 -----------------------------------> H3B03 + 3HCI
how to find out the basic radicals
some examples of RELATIVE MOLECULAR MASS OF SOLUTES BY RELATIVE LOWERING OF VAPOR PRESSURE
I think it''s funny how you guys say that you''re experts, but on the periodic table on the site you have the noble gases listed as inert elements. If whoever created that page act
Energy of orbit: (1) Increases as we move away from nucleus (2) Decreases as we move away from nucleus (3) Remains same as we move away from nucleus (4)None of the
What are three modifications to a polymer that can make it transparent? How will these modifications affect the mechanical properties of the polymer?
#questiolaw of chemical combinationn..
An electron has principal quantum number 3. The number of its (i) sub-shells and (ii) orbitals would be respectively: (1) 3 and 5 (2) 3 and 7 (3) 3 and 9
types of electromeric effect
verify the law of multiple proportions for an element X, which forms oxides having percentages of X equal to 77.4%, 63.2%,69.6% and 72.0%
The Basicity is 3 as there are 3 H atoms that can be displaced from compound.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd