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Explain the Graphical Technique of Linear Equations.
Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)
why arcsin(sinq)=pi-q [pi/2 3pi/2]
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The graphical technique of linear equations of solving a system consists of drawing the graphs of the equations of the system on the similar rectangular coordinate system. The coordinates of the point of intersection of the equations of the system would then be the solution.
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