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Find the maximum torque - I-section:
An I-section 150 × 80 mm has flanges 6 mm thick and web 4 mm thick. Discover the maximum torque that may be safely applied if the shear stress is limited to 30 N/mm2 and twist per metre length to 6o. G = 80 GPa.
Solution
∑ h t 2 = 2 × 80 × 62 + 150 × 42 = 8160 mm3
T = τmax . (1/3) (∑ h t 2 ) = 30 × (1 /3) × 8160 = 81, 600 N-mm
∑ h t3 = 2 × 80 × 63 + 150 × 43 = 44,160 mm4
θ= 3Tl / G (∑ h t3 )
⇒ 6 × (π /180) = 3T × 1000 / (80 × 103 × 44160)
∴ T = 123318 N-mm
∴ T = 44,160 N-mm (least value).
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