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Explain the geometry of CCl4
We first have to know the geometry of CCl4. This should be easy: it's tetrahedral, because the carbon is bonded to four identical groups. Now, as suggested in the hint, let's do a vector addition for the bond dipoles of every Cl-C-Cl pair. (Use a dipole arrow of arbitrary length as long as it is the similar for both. We'll use an arrow with the length of the C-Cl bonds.) Here's the result of the vector addition, which we've done graphically, for the first pair. Notice that, because the C-Cl bonds are identical, the resultant must bisect the angle among the two bonds
The energy of second Bohr orbit of the hydrogen atom is -328 kJ mol-1, hence the energy of fourth Bohr orbit would be: (1) - 41 kJ mol -1 (2) -1312 kJ mol -1 (3) -164
When the principal quantum number(n= 3) , the possible values of azimuthal quantum number(l ) is: (1) 0, 1, 2, 3 (2) 0, 1, 2 (3) - 2, - 1, 0, 1, 2
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