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Explain the geometry of CCl4
We first have to know the geometry of CCl4. This should be easy: it's tetrahedral, because the carbon is bonded to four identical groups. Now, as suggested in the hint, let's do a vector addition for the bond dipoles of every Cl-C-Cl pair. (Use a dipole arrow of arbitrary length as long as it is the similar for both. We'll use an arrow with the length of the C-Cl bonds.) Here's the result of the vector addition, which we've done graphically, for the first pair. Notice that, because the C-Cl bonds are identical, the resultant must bisect the angle among the two bonds
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The configuration 1s 2 2s 2 2p 5 3s 1 shows: (1) Excited state of O 2 - (2) Excited state of neon (3) Excited state of fluorine (4) Ground state of fluorine ato
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Distinguishing among enantiomers requires a technique that has a chiral attribute. (a) Boiling point does not distinguish among two enantiomers. (b) Optical rotation does ha
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