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Q. Explain how LEDs are arranged in a seven segment display ?
The illustration given below shows the basic layout of the segments in a seven- segment display. The segments themselves are identified with lower-case letters "a" through "g," with segment "a" at the top and then counting clockwise. Segment "g" is the center bar.
Most seven-segment digits also include a decimal point ("dp"), and some also include an extra triangle to turn the decimal point into a comma. This improves readability of large numbers on a calculator, for example. The decimal point is shown here on the right, but some display units put it on the left, or have a decimal point on each side.
Seven-segment displays can be constructed using different technologies. The three most common methods are
1. fluorescent displays (used in many line-powered devices such as microwave ovens and some clocks and clock radios)
2. liquid crystal displays (used in many battery-powered devices such as watches and many digital instruments)and
3. LEDs (used in either line-powered or battery-powered devices).
explain electromechanical instrument
1. A current carrying conductor is found to carry 10 μA at a given time slot from 5μs to 1.5 ms. Find the total number of electrons flowing in the conductor during this time slot.
(a) Carry out a topological analysis for the circuit shown in Figure 1. (i) Construct a graph for the circuit (ii) State the different trees you can choose. (b) Us
how do i figure up the resistance on Alumel and chromel wire stranded .080 dia 19 stands?
Energy stored in a capacitor During charging process by capacitor, it will get energy. Energy is stored in static form. The voltage in capacitor will enhance from 0 volt to E v
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i have an assignment. please help me.
Types of Power Diode According to their reverse recovery characteristics of power diodes it can be classified as follows: a. General purpose diodes b. Fas
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Consider the circuit shown in Figure in the t -domain as well as in the s-domain. Formulate the s-domain nodal equations and use MATLAB to solve for V A (s) and V B (s).
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