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Solve following.
|2x - 5 |= 9
Solution
Now, recall that absolute value does not just make all minus signs in plus signs. In order to solve these we've got to employ the formula above as in all cases the number on the right side of the equal sign is positive.
There actually isn't much to do here other than using the formula from above as noted above. All we have to note is that in the formula above p represents whatever is on the inside of the absolute value bars and so in this case we have,
2 x - 5 = -9 or 2 x - 5 = 9
At this instance we've got two linear equations which are easy to solve.
2 x = -4 or 2 x = 14
x = -2 or x = 7
Thus, we've got two solutions to the equation
x = -2 and x =7 .
Now, let's take a look at how to deal with equations for which b is zero or negative. We'll do this with an example.
Solve each of the following. |x - 2 | = 3x + 1 Solution At first glance the formula we utilized above will do us no good here. It needs the
Solve the system algebraically. x - 2y - 3z = negative-1 2x + y + z = 6 x + 3y - 2z = negative13
y = 4 - 3x /1 + 8x for x. Solution This one is very alike to the previous instance. Here is the work for this problem. y + 8xy = 4 - 3x 8xy + 3x = 4 - y X(8 y +3)
i need help withese two problems: y=x+4; (-7,1) and y=-1/2x +1; (4,2)
Solve following. 2 x - 4 = 10 Solution There actually isn't much to do other than plug into the formula. As with equations p merely represents whatever is within the a
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