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Let's begin with
x2 + bx
and notice that the x2 hold a coefficient of one. That is needed in order to do this. Now, to this lets add ( b /2) 2 . Doing this gives the given factorable quadratic equation.
x2 + bx + ( b /2)2 = (x+(b/2))2
This procedure is called accomplishing the square and if we do all the arithmetic properly we can guarantee that the quadratic will factor as a perfect square.
Let's do a couple of examples for completing the square before looking at how we employ this to solve out quadratic equations.
y=mx+b for x
how to do it
Solve following. 2x - 3 = 7 Solution Again, p represents the quantity within the absolute value bars thus all we have to do here is plug into the formula & then solve th
point a
Domain and Range The domain of any equation is the set of all x's which we can plug in the equation & get back a real number for y. The range of any equation is the set of all
For these properties we will suppose that x > 0 and y > 0 log b ( xy ) = log b x + log b y log b ( x/y) = log b x - log b y log b (x r ) = r log x If log
x^2 + 7x + 12 factor fully
how do u calculate algebra equations
verify Liouville''s formula for y'''' - y'''' -y'' + y = 0 in (0,1)
-1 1/2+ v = -3 3/10
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