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We require to check the derivative thus let's use v = 60. Plugging it in (2) provides the slope of the tangent line as -1.96, or negative. Thus, for all values of v > 50 we will have negative slopes for the tangent lines. When with v < 50, by looking at (2) we can notice that as v approaches 50, all the times staying greater than 50, the slopes of the tangent lines will approach zero and flatten out. As moving v away by 50 again, staying greater than 50, the slopes of the tangent lines will turn into steeper. We can here add in several arrows for the region above v = 50 as demonstrated in the graph as in following.
This above graph is termed as the direction field for the differential equation.
Suppose a unit circle, and any arc S on the unit circle in the first quadrant. No matter where S is provided, the area between S and the x-axis plus the covered area between S and
4 7 9 6
Perform each of the following algebraic expression as instruction says;- I.Multiply 5x+6m+4y by5 II.Divide 4ax+6ay-10az by 2a
Chain Rule : We've seen many derivatives. However, they have all been functions similar to the following kinds of functions. R ( z ) = √z f (t ) = t 50
what is 2+10000 =
Describe the Basic Concepts and Terminology? Somebody tells you that x = 5 and y = 3. "What does it all mean?!" you shout. Well here's a picture: This picture is what's
Evaluate the subsequent inverse trigonometric functions: Evaluate the subsequent inverse trigonometric functions. arcsin 0.3746 22° arccos 0.3746 69° arctan 0.383
find the area of this figure in square millimeter measure each segment to the nearest millmeter
1.A=the set of whole numbers less tan 4 ? 2.B=the set of prime numbers less than 19 ? 3.C=the set of first three days of week?
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