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We require to check the derivative thus let's use v = 60. Plugging it in (2) provides the slope of the tangent line as -1.96, or negative. Thus, for all values of v > 50 we will have negative slopes for the tangent lines. When with v < 50, by looking at (2) we can notice that as v approaches 50, all the times staying greater than 50, the slopes of the tangent lines will approach zero and flatten out. As moving v away by 50 again, staying greater than 50, the slopes of the tangent lines will turn into steeper. We can here add in several arrows for the region above v = 50 as demonstrated in the graph as in following.
This above graph is termed as the direction field for the differential equation.
Solution by Factorization, please solve quadratic equations by Factorization.
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identify 4 sketch the quadric surfaces
The following relation is not a function. {(6,10) ( -7, 3) (0, 4) (6, -4)} Solution Don't worry regarding where this relation came from. It is only on
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A wholesaler allows a discount of 20% on the list price to a retailer. The retailer sells at 5% discount on the list price.If a customer paid Rs 114 for an article,what profit is m
Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution) Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SI
what is 5x - 14x + 7x =
solve for x: logx9
if ab=25 . a(5,x)and b(2,5) . find x.
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