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We require to check the derivative thus let's use v = 60. Plugging it in (2) provides the slope of the tangent line as -1.96, or negative. Thus, for all values of v > 50 we will have negative slopes for the tangent lines. When with v < 50, by looking at (2) we can notice that as v approaches 50, all the times staying greater than 50, the slopes of the tangent lines will approach zero and flatten out. As moving v away by 50 again, staying greater than 50, the slopes of the tangent lines will turn into steeper. We can here add in several arrows for the region above v = 50 as demonstrated in the graph as in following.
This above graph is termed as the direction field for the differential equation.
ABCD is a parallelogram which AB and CD are divides by P and Q. Such that AP:PB=3:2 and CQ:QD=4:1. If PQ and AC are meet at R, show that AR=3/7AC.
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31/3=?
Find out the area under the parametric curve given by the following parametric equations. x = 6 (θ - sin θ) y = 6 (1 - cos θ) 0 ≤ θ ≤ 2Π Solution Firstly, notice th
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difference between scope and application of operation research
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