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We require to check the derivative thus let's use v = 60. Plugging it in (2) provides the slope of the tangent line as -1.96, or negative. Thus, for all values of v > 50 we will have negative slopes for the tangent lines. When with v < 50, by looking at (2) we can notice that as v approaches 50, all the times staying greater than 50, the slopes of the tangent lines will approach zero and flatten out. As moving v away by 50 again, staying greater than 50, the slopes of the tangent lines will turn into steeper. We can here add in several arrows for the region above v = 50 as demonstrated in the graph as in following.
This above graph is termed as the direction field for the differential equation.
Any point on parabola, (k 2 ,k) Perpendicular distance formula: D=(k-k 2 -1)/2 1/2 Differentiating and putting =0 1-2k=0 k=1/2 Therefore the point is (1/4, 1/2) D=3/(32 1/2
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multiply 9/19 times 95/7
Before we find into finding series solutions to differential equations we require determining when we can get series solutions to differential equations. Therefore, let's start wit
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