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The length of the diameter of the circle which touches the X axis at the point (1,0) and passes through the point (2,3) is ?Solution) If a circle touches the x-axis, its equation is(x-h)^2+(y-k)^2=k^2but it is given that the equation passes thru the point (1,0)=> 1+h^2-2h=0=> h=1,0and also that tha equation passes thru the point (2,3)=> 4+9-4h-6k+h^2=0=> 13-4-6k+1=0=> k=5/3=radiusdiameter = 2(radius)= 10/3
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Consider the following linear equations. x1-3x2+x3+x4-x5=8 -2x1+6x2+x3-2x4-4x5=-1 3x1-9x2+8x3+4x4-13x5=49
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