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The length of the diameter of the circle which touches the X axis at the point (1,0) and passes through the point (2,3) is ?Solution) If a circle touches the x-axis, its equation is(x-h)^2+(y-k)^2=k^2but it is given that the equation passes thru the point (1,0)=> 1+h^2-2h=0=> h=1,0and also that tha equation passes thru the point (2,3)=> 4+9-4h-6k+h^2=0=> 13-4-6k+1=0=> k=5/3=radiusdiameter = 2(radius)= 10/3
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Sketch the direction field for the subsequent differential equation. Draw the set of integral curves for this differential equation. Find out how the solutions behave as t → ∞ and
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