Diameter of the circle , Mathematics

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The length of the diameter of the circle which touches the X axis at the point (1,0) and passes through the point (2,3) is ?

Solution)  If a circle touches the x-axis, its equation is

(x-h)^2+(y-k)^2=k^2

but it is given that the equation passes thru the point (1,0)

=> 1+h^2-2h=0

=> h=1,0

and also that tha equation passes thru the point (2,3)

=> 4+9-4h-6k+h^2=0

=> 13-4-6k+1=0

=> k=5/3=radius

diameter = 2(radius)= 10/3


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