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Initial Conditions and Boundary Conditions
In many problems on integration, an initial condition (y = y0 when x = 0) or a boundary condition (y = y0 when x = x0 ) is given which uniquely determines the constant of integration. As a result of the unique determination of 'c', a specific curve can be singled out from a family of curves.
Example
For the boundary condition, y = 15 when x = 2, the integral y = ∫4dx is evaluated as follows:
y = ∫4dx = 4x + c
Substituting, y = 15, when x = 2
15 = 4(2) + c or c = 7
y = 4x + 7
Note that even though 'c' is specified, ∫4dx remains an indefinite integral because xn is unspecified. Thus, the integral 4x + 7 can assume an infinite number of possible values.
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3 3/4+(1 1/49*7/10)
Find no. of non negative integral solutions x 1 +x 2 +x 3 +4x 4 =20 Solution) 140. Break them into prime factors . Put 4 = 2^2 and every variable will have factors in 2,3,5 with
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12.+12+
time=2.82/4000
Evaluate: 30 - 12÷3×2 =
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