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Arc length Formula
L = ∫ ds
Where
ds √ (1+ (dy/dx)2 ) dx if y = f(x), a < x < b
ds √ (1+ (dx/dy)2 ) dy if x = h(y), c < y < d
Note that there is no limits were put on the integral as the limits will depend on the ds that we are using. By using the first ds will need x limits of integration and by using the second ds will need y limits of integration.
Idea of the arc length formula as a single integral with dissimilar ways to define ds will be suitable when we run across arc lengths in future sections. As well, this ds notation will be a nice notation for the later section as well.
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There is one final topic that we need to address as far as solution sets go before leaving this section. Consider the following equation and inequality.
Determine the area of the regular octagon with the following measurements. a. 224 square units b. 112 square units c. 84 square units d. 169 square units b. See
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How to Solving One-Step Equations? Equations, where one math operation is acting on the variable, can be solved in one step. The trick is to get the variable x by itself - isol
1/2+1/2
lbl 2 lcl 2 sin 2 θ
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27-81/3
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