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In figure, XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that XA+AR=XB+BR Ans: Since the length of tangents from externa
Before searching at series solutions to a differential equation we will initially require to do a cursory review of power series. So, a power series is a series in the form, .
Suggest me the solution: Consider the given universal set T and its subjects C, D and E T = {0, 2, 4, 6, 8, 10, 12} C = {4, 8,} D = {10, 2, 0} E = {0} Find out
Calculus with Matrices There actually isn't a whole lot to it other than to just ensure that we can deal along with calculus with matrices. Firstly, to this point we've onl
solve for x and y 2x+3y=12 and 30x+11y=112
to use newspaper and report on share and dividend
express each logariths in terms of log3 P and log3 Q. 1. log3 P^2 Q^3
proof of chebychevs lemma
A piece of cardboard in the shape of a trapezium ABCD & AB || DE, ∠ BCD = 900, quarter circle BFEC is removed. Given AB = BC = 3.5 cm, DE = 2 cm. Calculate the area of remaining p
find the radius of circumcircle of an equilateral triangle of 6root3 one side.
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