Computation of a dfa or nfa, Theory of Computation

Assignment Help:

Computation of a DFA or NFA without ε-transitions

An ID (q1,w1) computes (qn,wn) in A = (Q,Σ, T, q0, F) (in zero or more steps)

2490_Computation of a DFA or NFA.png

if there is a sequence of IDs (q1,w1), . . . qn,wn)) in which, for all i > 1, 899_Computation of a DFA or NFA1.png

A computation of an FSA A on input w is a computation from the initial ID (q0,w) to a terminal ID: ((q0,wi, . . . , (q, ε)).

The fact that |-A is no longer partial functional implies that we can no longer speak of the computation of A on hq1,w1i. What's more, while every computation is ?nite, it is no longer true that they all take exactly |w1| steps. Computations end when they reach an ID with no successor; this can now be either because the entire input was scanned or because an ID hq, σ  wi was reached for which δ(q, σ) = ∅. Only the ?rst case represents successful processing of w1 by A; we need to be careful to distinguish "halting" computations from those that "crash".


Related Discussions:- Computation of a dfa or nfa

Pendulum Swings, how many pendulum swings will it take to walk across the c...

how many pendulum swings will it take to walk across the classroom?

Finiteness of languages is decidable, To see this, note that if there are a...

To see this, note that if there are any cycles in the Myhill graph of A then L(A) will be infinite, since any such cycle can be repeated arbitrarily many times. Conversely, if the

Mapping reducibility, Can you say that B is decidable? If you somehow know...

Can you say that B is decidable? If you somehow know that A is decidable, what can you say about B?

Chomsky normal form, s->0A0|1B1|BB A->C B->S|A C->S|null find useless symbo...

s->0A0|1B1|BB A->C B->S|A C->S|null find useless symbol?

Operations on strictly local languages, The class of Strictly Local Languag...

The class of Strictly Local Languages (in general) is closed under • intersection but is not closed under • union • complement • concatenation • Kleene- and positive

Synthesis theorem, Kleene called this the Synthesis theorem because his (an...

Kleene called this the Synthesis theorem because his (and your) proof gives an effective procedure for synthesizing an automaton that recognizes the language denoted by any given r

Myhill-nerode theorem, This close relationship between the SL2 languages an...

This close relationship between the SL2 languages and the recognizable languages lets us use some of what we know about SL 2 to discover properties of the recognizable languages.

Exhaustive search, A problem is said to be unsolvable if no algorithm can s...

A problem is said to be unsolvable if no algorithm can solve it. The problem is said to be undecidable if it is a decision problem and no algorithm can decide it. It should be note

Ogdens lemma, proof ogdens lemma .with example i am not able to undestand ...

proof ogdens lemma .with example i am not able to undestand the meaning of distinguished position .

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd