Computation of a dfa or nfa, Theory of Computation

Assignment Help:

Computation of a DFA or NFA without ε-transitions

An ID (q1,w1) computes (qn,wn) in A = (Q,Σ, T, q0, F) (in zero or more steps)

2490_Computation of a DFA or NFA.png

if there is a sequence of IDs (q1,w1), . . . qn,wn)) in which, for all i > 1, 899_Computation of a DFA or NFA1.png

A computation of an FSA A on input w is a computation from the initial ID (q0,w) to a terminal ID: ((q0,wi, . . . , (q, ε)).

The fact that |-A is no longer partial functional implies that we can no longer speak of the computation of A on hq1,w1i. What's more, while every computation is ?nite, it is no longer true that they all take exactly |w1| steps. Computations end when they reach an ID with no successor; this can now be either because the entire input was scanned or because an ID hq, σ  wi was reached for which δ(q, σ) = ∅. Only the ?rst case represents successful processing of w1 by A; we need to be careful to distinguish "halting" computations from those that "crash".


Related Discussions:- Computation of a dfa or nfa

Decidability, examples of decidable problems

examples of decidable problems

Closure properties of recognizable languages, We got the class LT by taking...

We got the class LT by taking the class SL and closing it under Boolean operations. We have observed that LT ⊆ Recog, so certainly any Boolean combination of LT languages will also

#title., distinguish between histogram and historigram

distinguish between histogram and historigram

Local and recognizable languages, We developed the idea of FSA by generaliz...

We developed the idea of FSA by generalizing LTk transition graphs. Not surprisingly, then, every LTk transition graph is also the transition graph of a FSA (in fact a DFA)-the one

Computation of a dfa or nfa, Computation of a DFA or NFA without ε-transiti...

Computation of a DFA or NFA without ε-transitions An ID (q 1 ,w 1 ) computes (qn,wn) in A = (Q,Σ, T, q 0 , F) (in zero or more steps) if there is a sequence of IDs (q 1

Union, Intuitively, closure of SL 2 under intersection is reasonably easy ...

Intuitively, closure of SL 2 under intersection is reasonably easy to see, particularly if one considers the Myhill graphs of the automata. Any path through both graphs will be a

Automata, how to prove he extended transition function is derived from part...

how to prove he extended transition function is derived from part 2 and 3

Numerical integration, what problems are tackled under numerical integratio...

what problems are tackled under numerical integration

Brain game, If the first three words are the boys down,what are the last th...

If the first three words are the boys down,what are the last three words??

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd