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f(x)+f(x+1/2) =1f(x)=1-f(x+1/2)0∫2f(x)dx=0∫21-f(x+1/2)dx0∫2f(x)dx=2-0∫2f(x+1/2)dxtake (x+1/2)=vdx=dv0∫2f(v)dv=2-0∫2f(v)dv2(0∫2f(v)dv)=20∫2f(v)dv=10∫2f(x)dx=1
The interval of validity for an IVP along with initial conditions: y(t 0 ) = y 0 or/and y (k) (t 0 ) = y k There is the largest possible interval on that the solution is va
Learning geometric progression vis-á-vis arithmetic progression should make it easier. In geometric progression also we denote the first t
what is 90005+890+098876-89
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Average Function Value The average value of a function f(x) over the interval [a,b] is specified by, f avg = (1/b-a) a ∫ b f(x) dx Proof We know that the average
Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. a) Set up an equation for the perimeter involving
The scores of students taking the ACT college entrance examination are normally distributed with a mean m = 20.1 and a standard deviation s = 5.8. A single student is selected a
Suppose a unit circle, and any arc S on the unit circle in the first quadrant. No matter where S is provided, the area between S and the x-axis plus the covered area between S and
1. Discuss lyapunov function theory and how it can be used to prove global assmptotic stability of solutions.(Give an example form natural and engineering sciences.) --- Draw le
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