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The main problem is to find β in this equation:
F(u) = ωu(u-β)(1-u)
If is it β ≤ -1 ????
Or
-1 ≤ β ≤ 0
β > 0 ???
The solution step:
1. F(u) = ωu(u- β) (1-u)
2. F'(u) = ω(u-β)(1-u) + ωu(1-u) - ωu (u-β)
= ωu - ωu2 - ωβ + ωβu + ωu(1-u) - ωu(u-β)
= -3ωu2 + 2ωu + 2ωβu - ωβ.
3. Now we have find umax (Hint- umax: F'(u)= 0.)
4. we have to find max F = F(umax) from this we can found β = ???
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