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The following table shows several bacterial strain lac operon genotypes (some are partial diploids).
a) Fill in the blanks in the “lactose absent” and “lactose present” columns in this table. (+) means significant levels of active ß-galactosidase enzyme can be detected. (–) means no significant levels of active ß-galactosidase enzyme. The first line is filled in for reference.Strain genotypeLactose absentLactose present1. lacI+ lacP+ lacO+ lacZ+ lacY+2. lacI+ lacP+ lacOc lacZ+ lacY+3. lacI+ lacP+ lacOc lacZ– lacY+4. lacIs lacP+ lacOc lacZ+ lacY+5. lacI– lacP+ lacO+ lacZ+ lacY+ / lacI+6. lacIs lacP+ lacO+ lacZ+ lacY+/ lac I+
b) If lactose is absent and glucose is present in the culture medium of strain 4, will significant levels of active ß-galactosidase enzyme be detected? Explain… in brief, just because there is lots of room left, you don’t need to fill it.
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Imagine a population in which an autosomal recessive disease mutation has an allele frequency of 0.04 (q = 0.04).
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q1. if molecular mass of a carbon atom is 12 the mass of a hydrogen atom is 1 and the mass of an oxygen atom is 16
Suppose that you perform the following monohybrid cross in dogs: Aa X Aa, in which the dominant A allele produces black coat color and the recessive a allele produces a white coat color.
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