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Polynomials like 5x4 + 2x3 + 7x2 + 10x - 8 can be represented by using arrays. Arithmetic operations such as addition & multiplication of polynomials are common and most often; we have to write down a program to implement these operations.
The easiest way to represent polynomial of degree 'n' is to store up the coefficient of (n+1) terms of the polynomial in an array. To gain this, each of the elements of the array must contain two values, namely, exponent and coefficient. Whereas maintaining the polynomial, it is supposed that the exponent of each of the successive term is less than that of the earlier term. Once we create an array to represent a polynomial, we can employ such an array to perform common polynomial operations such as addition & multiplication.
Program 2 accepts 2 polynomials as input & adds them.
Define neotaxonomy. Discuss how electron microscopy can help in solving a zoological problem faced by taxonomist.
Given is the structure of an AVL tree: struct avl { struct node *left; int info; int bf; struct node *right; }; 2) A multiway tree of n order is an ord
Q. Develop a representation for a list where insertions and deletions can be done at either end. Such a structure is known as a Deque (Double ended queue). Write functions for inse
Example: Assume the following of code: x = 4y + 3 z = z + 1 p = 1 As we have been seen, x, y, z and p are all scalar variables & the running time is constant irrespective
The smallest element of an array's index is called its Lower bound.
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write an algorithm for multiplication of two sparse matrices using Linked Lists
null(nil) = true // nil refer for empty tree null(fork(e, T, T'))= false // e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true leaf(
Conceptually, the stack abstract data type mimics the information kept into a pile on a desk. Informally, first we consider a material on a desk, where we might keep separate stack
Binary tree creation struct NODE { struct NODE *left; int value; struct NODE *right; }; create_tree( struct NODE *curr, struct NODE *new ) { if(new->val
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