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Algorithm for insertion of any element into the circular queue:
Step-1: If "rear" of the queue is pointing at the last position then go to step-2 or else Step-3
Step-2: make the "rear" value as 0
Step-3: increase the "rear" value by one
Step-4: a. if the "front" points where "rear" is pointing & the queue holds a not NULL value for it, then it's a "queue overflow" state, thus quit; else go to step-b
b. Insert the new value for the queue position pointed by the "rear"
According to this, key value is divided by any fitting number, generally a prime number, and the division of remainder is utilized as the address for the record. The choice of s
Q. What do you understand by the term Hashing? How do the collisions occur during hashing? Explain the different techniques or methods for resolving the collision.
What do you mean by hash clash? Hashing is not perfect. Occasionally, a collision occurs when two different keys hash into the same hash value and are assigned to the same arra
Question 1 Explain how the shuttle sort algorithm works by making use of the following list of integers:11, 4, 2, 8, 5, 33, 7, 3, 1, 6. Show all the steps. Question 2
Write an algorithm in the form of a flowchart that: inputs top speeds (in km/hr.) of 5000 cars Outputs fastest speed and the slowest speed Outputs average (mean) s
how to write a function of area of a circle using python
Searching is the procedure of looking for something. Searching a list containing 100000 elements is not the similar as searching a list containing 10 elements. We discussed two sea
Ruby implementation of the Symbol ADT Ruby implementation of the Symbol ADT, as mentioned, hinges on making Symbol class instances immutable that corresponds to the relative la
(1) (i) Add the special form let to the metacircular interpreter Hint: remember let is just syntactic sugar for a lambda expression and so a rewrite to the lambda form is all t
Step 1: Declare array 'k' of size 'n' i.e. k(n) is an array which stores all the keys of a file containing 'n' records Step 2: i←0 Step 3: low←0, high←n-1 Step 4: while (l
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