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Equation of line joining(0,0)and point of intersection of X2+Y2+2XY=4 , 3x2+5y2-xy=7 is solution) The two equations above represent pair of straight lines. We can complete the square and arrive at the 4 line equatons and find their point of intersecrtion.Simple method (by mere observation) we can say X=1&Y=1 satisfies both the equation.therfore, Line passing through origin and (1,1) is :X=Y.=>X=Y is the reqd line equation
( a+2b)x + (2a - b)y = 2, (a - 2b)x + (2a +b)y = 3 (Ans: 5b - 2a/10ab , a + 10b/10ab ) Ans: 2ax + 4ay = y , we get 4bx - 2by = -1 2ax+ 4ay = 5 4bx- 2by = - 1
Pre-operational Stage : This period of a child's cognitive development usually begins at the age of 2, and lasts until about the age of 6. Thus, it usually coincides with the pre
EVERY TIME I TRY TO DO ANY KIND OF FRACTIONS WELL MULTIPLYING I ALWAYS GET IT WRONG
Under this section we're going to go back and revisit the concept of modeling only now we're going to look at this in light of the fact as we now understand how to solve systems of
Arc Length with Parametric Equations In the earlier sections we have looked at a couple of Calculus I topics in terms of parametric equations. We now require to look at a para
Scalar Multiplication - Vector arithmetic Another arithmetic operation that we wish to look at is scalar multiplication. Specified the vector a → = (a 1 , a 2 , a 3 ) and any
Exponential Functions : We'll begin by looking at the exponential function, f ( x ) = a x We desire to differe
Mutually Exclusive Events A set of events is said to be mutually exclusive if the occurrence of any one of the events precludes the occurrence of any of the other events for i
The alternative hypothesis When formulating a null hypothesis we also consider the fact that the belief may be found to be untrue thus we will refuse it. Therefore we formula
Solve -10 cos(3t )= 7 on [-2,5]. Solution Let's first get the inverse cosine portion of this problem taken care of. cos(3 t )= - 7/10 ⇒ 3t = cos -1 ( - 7
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