Permatuation and combination problem, Mathematics

4 boys and 4 girls are to seated in arow

i)no. of girls sit together

ii)not all girls sit together

iii)boys and girls are altenate to each other

iv)if a particular boy and girl are a couple find no. of ways they are never together

v)in how many ways 4 boys and 4 girls can be seated in alternate arrangement manner

Solution:)
1.5P5*4P4

2.8P8-5P5*4P4

3.2*4P4*4P4

Posted Date: 3/8/2013 6:38:22 AM | Location : United States







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