A shuttlecock used for playing badminton has the shape of a frustum of a Cone mounted on a hemisphere.  The external diameters of the frustum are 5 cm and 2 cm, and the height of the entire shuttlecock is 7cm.   Find the external surface area.(Ans: 74.26cm2)

Ans: r₁ = radius of lower end of frustum = 1 cm

r₂   = radius of upper end = 2.5 cm

l = = 6.18 cm

External surface area of shuttlecock = π (r₁ + r₂) l + 2π r² 1

On substituting we get,   = 74.26 cm²

 

 

Posted Date: 4/10/2013 6:51:18 AM | Location : United States

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