Find out m.i. of t section, Mechanical Engineering

Q. Find out M.I. of T section as shown in figure given below about X-X and Y-Y axis through center of gravity of the section.

 

2444_MI.png

Figure

Sol.: As the diagram is symmetrical about y axis that is X = 0

A1 = 150 × 50 = 7500 mm2

A2 = 50 × 150 = 7500 mm2

y1 = (150 + 50/2) = 175 mm

y2 = 150/2 = 75 mm

Y = (A1y1  + A2y2)/(A1  + A2)

= (7500 × 175 + 7500 × 75)/(7500 + 7500) = 125 mm

C.G. = (0,125)

Moment of inertia about x-x axis = IXX  = IXX1  + IXX2

1979_MI1.png
Moment of inertia (M.I.) about y-y axis =  Iyy =  Iyy1 +  Iyy2
Since 962_MI2.png
568_mi3.png

Posted Date: 10/20/2012 8:47:00 AM | Location : United States







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