Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Explain from the drain characteristics that a JFET has infinite resistance?
When VGS = 0v
when a positive voltage Vds has been applied across the channel and the gate has been connected directly to the source to establish the condition VGS=0v.The result is a gate and source terminal at the same potential and a depletion region in the low end of each p- material .the instant the voltage VDD= VDS is applied ,the electrons will be drawn to the drain terminal ,establishing a conventional current ID, here ID=IS..It is important to note that the depletion region near the top of both the p-materials are wider this is due to the fact that the upper region is more reverse biased than the lower region that is the the greater the applied reverse bias ,the wider the depletion region .the fact that the p-n junction is reverse biased for the length of the channel results in a gate current of zero amperes .The fact that IG = 0A is an important characteristics of the JFET .
As the voltage VDS is increased from 0V to a few volts ,the current will increase as determined by ohms law and the plot of ID versus VDS will appear as shown in the graph.The relative straightness of the plot reveals that for the region of low values ot VDS, the resistance is essentially constant . As VDS increases and reaches upto a value vp,the depletyion region will widen ,causing a noticeable change in the channel width.The reduced path of conduction causes the resistance to increase and the curve in the graph to occur.The more horizontal the curve the higher the resistance ,suggesting that the resistance is approaching infinite ohms in the horizontal region.
If VDS is increased to a level where it appears that the two depletion regions would touch a condition reffered to as pinch -off will result .The level of VDS that establishes this condition is refferd to as pinch -off voltage and it is denoted by VP.In actuality the term pinch-off is a misnomer in that it suggests the current ID is pinched -off and drops of to 0A .In reality a very small channel exsists ,with a current of very high density .The fact that ID does not drop off at pinch-off and maintains saturation level .It is verified by the fact that the absence of a drain current would remove the possibility of different poyential levels through the n-channel material to establish the varying levels of reverse bias along the p-n junction .The result would be a loss of the depletion region distribution that caused pinch off in the first place.As VDS is increased by VP the region of close encounter between the two depletion regions will increase in length along the channel ,but the level of ID remains exactly the same ,therefore once VDS>VP the JFET has the characteristics of a current source.
how did shockley derived his equation
Q. Cause of sparking at the brushes of a DC Motor? Ans: Sparking at the brushes can be occur due to poor quality of carbon brushes, loose connection, poor armature of carbon
A 10-hp, 230-V, 500-r/min shunt motor, having a full-load armature current of 37 A, is started with a four-point starter. The resistance of the armature circuit, including the inte
what is crossmagnetisation in dc generator
Q. pn-Junction under Bias? Let an external source be connected between the p- and n-regions, as shown in Figure (a). (b) shows the circuit representation of the pn-junction or
please give me the ckt for wein bridge oscillator with 5KHz frequency using transister (with exact values of resistor and capacitor).
For sign flag RP ( Return on Plus ) and RM ( Return on no minus ) Instructions RM returns from the subroutine to the calling program if sign flag is set (S=1). The in
Q. The flux-density distribution in the air gap of a 60-Hz, two-pole, salient-pole machine is sinusoidal, having an amplitude of 0.6 T. Calculate the instantaneous and rms value
Q. Write short note on Quantization? Quantization: This is first step in PCM. Total amplitude range of the modulating signal is divided into a number of standard levels calle
In this case, the armature is connected in series with the field coils. Thus I a = I f = I NB. At starting, the back emf is zero (because the m
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd