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CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a memory location. For the purpose of comparison, it subtracts the source operand from the destination operand but does not stock up the result anywhere. The flags are affected and depending on the result of the subtraction. If both of the operands are equal to zero flag is set. If the source operand is higher than the destination operand, carry flag is set or else is reset. The instance of this instruction are following:
Example :
1. CMP BX, 0100H Immediate
2. CMP 0100 Immediate [AX implicit]
3. CMP [5000H],OIOOH Direct
4. CMP BX, [SI] Register indirect
5. CMP BX, CX Register
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
General Bus Operation The 8086 has a joined data and address bus commonly referred to as a time multiplexed address and data bus. The major reason behind multiplexing address
#question. counters using 8051.
Power Pc : A Power PC is a microprocessor designed to meet a standard, which was combining designed by Motorola, Apple and IBM. The PowerPC standard specifies a common instruc
Pointer and Index Registers The pointers contain offset within the specific segments. The pointers BP, IP and SP generally containoffsets within thedata, code and stack segment
DMA DMA stands for Direct Memory Access It is uses same Address/Data lines on ISA bus It controls the ISA bus instead of the processor ("bus master") Floppy
Write an application that does the following: (1) fill an array with 50 random integers; (2) loop through the array, displaying each value, and count the number of negative values;
• To develop an assembly language program to control a "simulated" intelligent domestic lighting system with the intention of deterring burglary. • To produce a schematic circuit d
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I need to estimate the value of a definite integral using Riemann Sums and For our estimation let f(x) = x2 ,a=0, b=10 and n=5. Where a is the lower bound, b is the upper bound and
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