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CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a memory location. For the purpose of comparison, it subtracts the source operand from the destination operand but does not stock up the result anywhere. The flags are affected and depending on the result of the subtraction. If both of the operands are equal to zero flag is set. If the source operand is higher than the destination operand, carry flag is set or else is reset. The instance of this instruction are following:
Example :
1. CMP BX, 0100H Immediate
2. CMP 0100 Immediate [AX implicit]
3. CMP [5000H],OIOOH Direct
4. CMP BX, [SI] Register indirect
5. CMP BX, CX Register
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)
1. Write a program that will generate an array of ten random 32-bit integers, and that will display on the monitor the numbers followed by either the words " has the fourth bit se
Write a program to merge two sorted arrays to create a third sorted array containing all values from the two original arrays. Merge is a key component to the mergesort algorithm.
CALL : Unconditional Call:- This instruction is utilized to call a subroutine from a basic program. In case of assembly language programming, the term procedure is utilized int
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define accounting.briefly explain the accounting concepts which guide the accountant at the recording stage.
Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
Write an 8086 program to find out the number of positive numbers and negative numbers from a given series of signed numbers include flow chart ..
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