Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
CISC Characteristics :
The design of an instruction set for a computer might take into consideration not only machine language constraints, but also the requirements imposed on the use of high-level programming languages. The translation from high-level to machine language programs is done by means of a compiler program. One cause for the trend to provide a complex instruction set is the desire to simplify the compilation and improve the overall computer performance. The task of a compiler is to produce a sequence of machine instructions for each high-level language statement. The job is simplified if there are machine instructions that implement the statements directly. The important aim of CISC architecture is to attempt to provide a single machine instruction for each statement that is written in a high-level language .An Examples of CISC architectures are the Digital Equipment Corporation VAX computer and the IBM 370 computer.
The main characteristics of CISC architecture are:
1. A large number of instructions-usually from 100 to 250 instructions.
2. Some instructions that perform specialized tasks and are used infrequently.
3. A vast variety of addressing modes-typically from 5 to 20 different modes.
4. Variable-length instruction formats.
5. Instructions that manipulate operands in memory.
$NOMOD51 $NOSYMBOLS ;***************************************************************************** ; Spring 2013 Project ; ; FILE NAME : Project.ASM ; DATE : 3/30/20
Linking a program The DOS linking program LINK.EXE links the different object modules of function library routines and source program to produce an integrated executable code o
Write an assembly language program that will: accept keyboard input of a positive integer value N; compute the sum S= 1+ 2 + 3 + ... + N; print (output) the computed su
program to accept 23 students name using while loop let your variable control the value negative 4
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
errorlevel -302 ;prevents error code for this chipset __config 0x373A ;chip config PIC spec page 146 processor 16F877A ;chipset reset code
Problems: 1. Write a single program. Each of the problems (2-4) should be written within a procedure. Your “main” procedure should call each procedure. Before calling each proc
chp 3 of assemly
Cache components The cache sub-system may be divided into 3 functional blocks: Tag RAM, SRAM and theCache Controller. In real designs, these blocks can be implemented by multi
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd