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Why is Translation Look-aside Buffers (TLBs) important?
The implementation of page-table is completed in the following manner:
The two-memory access problem can be solved through the utilization of a special fast-lookup hardware cache termed as translation look-aside buffers (TLBs) or associative memory. A set of associative registers is made of high-speed memory; here each register contains two parts: a key and a value. While the associative registers are presented along with an item, this is compared with all keys concurrently. If the item is determined, the consequent value field is the output.
Q. Explain the odd-even transposition algorithm? The algorithm needs one 'for loop' beginning from I=1 to N it implies that N times and for every value of I, one 'for loop' of
Illustrate about the Problem statement Problem statement would not be incomplete, inconsistent and ambiguous. Try to state the requirements precisely and point to point. Do no
Q. Measure of speed in Page or line Printer? Measure of speed relies on whether the printer is a Page Printer or Line. Printer: Let's understand these: Line Printer:
Hardware Cost It refers to the cost involved in the execution of an interconnection network. It consists of the cost of switches, connectors, , arbiter unit, interface logic an
Two popular encryption techniques to ensute secured transactions on the net? 1. Translation table 2. Word/byte rotation and XOR bit masking.
Q. What is the dissimilarity between dynamic strain aging and strain aging? Answer:- Strain aging could be explains as "normal wear and tear" or the fatigue that is experi
The Karnaugh map for a SOP function is given below in figure. Determine the simplified SOP Boolean expression. Ans. F= B'C' + A'C'D + B'D'
Computer have many type of memory like primary memory , Auxiliary memory , Cache memory , buffer memory ,virtual memory , The work of all memory heterogeneously primary memory
Evaluate x = A ‾.B + C ( ) using the convention A = True and B = False. Ans. Simplify given expression x = A ‾ .B + C ( ) as = A ‾ B + C (A ‾ + D ‾ ) (As = A ‾ +D ‾ usin
The decimal equivalent of (1100) 2 is ? Ans. (1100) 2 = (12) 10
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