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Carl worked three more than twice as many hours as Cindy did. What is the maximum amount of hours Cindy worked if together they worked 48 hours at most?
Let x = the amount of hours Cindy worked. Let 2x + 3 = the amount of hours Carl worked. Because the total hours added together was at most 48, the inequality would be (x) + (2x + 3) ≤ 48. merge such as terms on the left side of the inequality: 3x + 3 ≤ 48. Subtract 3 from both sides of the inequality: 3x + 3 - 3 ≤ 48 - 3; simplify: 3x ≤ 45. Divide both sides of the inequality by 3: 3x/3 ≤ 45/3; the variable is now alone: x ≤ 15. The maximum amount of hours Cindy worked was 15.
If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) y′ + q (t ) y = 0 So the Wronskian of the two solutions is, W(y 1 ,y 2 )(t) = =
this subject is numerical analysis
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