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∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + cDetailed derivation of∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx
= ∫(cosec2x - cosecxcotx)/(cosecx - cotx) dx
= log[cosecx - cotx] = log[(1-cosx)/sinx]
= log[2sin2(x/2)/2sin(x/2)cos(x/2)]
= log[tan(x/2)]
An investment advisory firm manages funds for its numerous clients. The company uses an asset allocation model that recommends the portion of each client's portfolio to be invested
SOLVE AND GRAPH THE PARABOLA NOTE: WRITE YOUR SOLUTIONS AND COMPLETE EQUATION OF GRAPH SPOINTS EACH 1. V(0,0) (0.2) P-2 2. V(0,0) E-5,0) P=-5 3. V(4-3) F(4,-2) P=1 4. V-1,5)
A rectangular field is to be fenced in completely. The width is given as 22 yd and the total area is 990 yd 2 . Determine the length of the field? a. 31 yd b. 45 yd c. 968
HOLISTIC MARKETING
how many mg are there in g?
The area of a rectangle is 24 square inches. The length of the rectangle is 2 inches more than the width. How many inches is the width? Let x = the number of inches in the widt
20+20
Initial Conditions and Boundary Conditions In many problems on integration, an initial condition (y = y 0 when x = 0) or a boundary condition (y = y
how can i build Y=2x
solving
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