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What is the condition for resonance?
Condition for resonance:
The condition of frequency of the oscillatory circuit is equal to frequency of the vibrating rod as:
1/(2 Π (√LC)) = 1/(2l (√E/ρ))
Here, l is the length of the rod.
E is the young's modulus of material of rod.
ρ is the density of material of the rod.
A surveyor is using a magnetic compass 7.1 m below a power line in which there is a steady current of 120A. What is the magnetic field in microteslas at the site of the compass due
why +ve half clip below than v_0.7v
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