If 65% of the populations have black eyes, 25% have brown eyes and the remaining have blue eyes. What is the probability that a person selected at random has (i) Blue eyes (ii) Brown or black eyes (iii) Blue or black eyes (iv) neither blue nor brown eyes         (Ans: 1/10 , 9/10 , 3/4 , 13/20 )

Ans:          No. of black eyes = 65

No. of Brown eyes = 25

No. of blue eyes =     10

Total no. of eyes = 180

i)  P (Blue eyes) =  10/100  =  1/10

ii) P (Brown or black eyes) =  90/100  =  9/10

iii) P(Blue or black eyes) =  75/100 = 3/4

iv)P(neither blue nor brown eyes) =  65/100 =  13/20