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If 65% of the populations have black eyes, 25% have brown eyes and the remaining have blue eyes. What is the probability that a person selected at random has (i) Blue eyes (ii) Brown or black eyes (iii) Blue or black eyes (iv) neither blue nor brown eyes (Ans: 1/10 , 9/10 , 3/4 , 13/20 )
Ans: No. of black eyes = 65
No. of Brown eyes = 25
No. of blue eyes = 10
Total no. of eyes = 180
i) P (Blue eyes) = 10/100 = 1/10
ii) P (Brown or black eyes) = 90/100 = 9/10
iii) P(Blue or black eyes) = 75/100 = 3/4
iv)P(neither blue nor brown eyes) = 65/100 = 13/20
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