Vhdl, Electrical Engineering

Assignment Help:
Im doing my final year project and Im stuck in vhdl coding. The main mission of this project is to design and build a tap changer which is going to be fitted to power transformers for regulation of the output voltage to required levels for the Micro Grid.
The tap changer system will consist of 9 changers with a 4v step having 9 switches/ Relays. 5 relays will be in the first stage, second stage consist of 3 relays, third stage has got 2 relays and the final stage has 1 relay. The voltage range of the tap changer 399- 431, Tap changer will perform step-up or step-down duties depending on what is requires. ( Tap1-399volts, Tap2 403volts, Tap3 407volts, Tap4 411volts, Tap5 415volts, Tap6 419volts, Tap7 423volts, Tap8 427volts, Tap9 2311volts. )
Im using vhdl programme to control the switches( switch1 to switch 9) using Spartan 3 board and displaying the selected switch on the board. I have written a bit of the the code which is at the bottom and im completely stuck I just need help in finishing the code and have attached the You are my last hope .

use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;
entity UPDOWNCOUNTERHOLD is
Port ( Clock : in STD_LOGIC;
Reset : in STD_LOGIC;
-- Automatic : in STD_LOGIC;--- AUTOMATIC SELECTION
Tap_set : in STD_LOGIC;--- ACTIVATES THE TAP SELECTED
SW : in STD_LOGIC_VECTOR (8 downto 0);---- switch for Tap 1 up to 9
--SSG_input : in std_logic_vector(3 downto 0); -- input to seven segment display
Tap_Output: out STD_LOGIC_VECTOR (8 downto 0);-- Tap output
SSG_out : out STD_LOGIC_VECTOR (6 downto 0);--- SEVEN SEGMENT OUTPUT DISPLAY
AN0 : out STD_LoGIC);
end UPDOWNCOUNTERHOLD;

architecture Behavioral of UPDOWNCOUNTERHOLD is

Constant Max_tap :integer := 9;-- referance for the switches
signal Max_tap_vector:std_logic_vector(3 downto 0);
Signal Auto :STD_LOGIC;---- signal for Automatic
Signal Tap_select :STD_LOGIC;-----signal for Tap_set
Signal Switch :std_logic_vector(3 downto 0);----- signal for SW
Signal Tap_out :std_logic_vector(3 downto 0);----- signal for Tap_Output
Signal Seven_segment :std_logic_vector(6 downto 0);----- signal for the seven segment display
SIGNAL S_SW :std_logic_vector(3 DOWNTO 0);----- SIGANAL FOR SWITCH IN MAUNAL/TAP SELECT
BEGIN
PROCESS(Clock,Reset,Tap_set)

BEGIN

IF (Reset = ''1'') THEN

Tap_out <= "0001"; -- reset to tap 1
Seven_segment <= "1001111" ;-- reset it to display tap 1

ELSIF (rising_edge(Clock)) THEN

IF (Tap_set = ''1'') THEN

Tap_Out<= Switch; -- running on manual output depends on the tap switch which is on

end if;

IF (Tap_out > Max_tap) THEN ---- If the output is more than 9 reset

Tap_Out<= "0001"; --- reset to tap 1
Seven_segment <= "1001111" ;-- reset it to display tap 1

IF (conv_integer(Max_tap)) = Max_tap_vector then

--IF (conv_integer(Max_tap_vector)) = Max_tap then------converting interger
--OTHER_VECTOR<=(others =>''0'');
END IF;
END IF;
End if;
END PROCESS;
PROCESS(SW,Clock)
Begin
--S_SW <= SW(3 DOWNTO 0) ;
case SW is
when "0001"=>SSG_out<= "1001111";
when "0010"=>SSG_out<= "0010010";
when "0011"=>SSG_out<= "0000110";
when "0100"=>SSG_out<= "1001100";
when "0101"=>SSG_out<= "0100100";
when "0110"=>SSG_out<= "0100000";
when "0111"=>SSG_out<= "0001111";
when "1000"=>SSG_out<= "0000000";
when "1001"=>SSG_out<= "0000100";
--nothing is displayed when a number more than 9 is given as input.
when others =>SSG_out<="1111111" ;
end case ;
END PROCESS;
end Behavioral;
?

Related Discussions:- Vhdl

Compute the attenuation, Q. A rectangular air-?lled RG-52/U is made of bras...

Q. A rectangular air-?lled RG-52/U is made of brass (ρ = 3.9 × 10-8 m) and has dimensions a = 22.86 mm and b = 10.16 mm. (a) Determine ¯ Z0(= R0) at the limits of the practica

Network analysis, expain how to do proper initial approximatio for the give...

expain how to do proper initial approximatio for the given cct....... by a example

Common-emitter configuration, Q. Common-Emitter Configuration? The emit...

Q. Common-Emitter Configuration? The emitter part of a circuit being common to both the input and the output portions, Figure (a) illustrates a common-emitter (CE) BJT amplifie

Bad effects of armature reactions, Q.  What is meant by armature reaction....

Q.  What is meant by armature reaction. Explain briefly the bad effects of armature reactions.   Sol. By armature reaction is meant the effect of magnetic field set up

Define gain and phase responses, Define Gain and Phase Responses? Expre...

Define Gain and Phase Responses? Expressing H(e j? ) in polar form as:   H (e j? ) = G (?) e jφ(?) G(?) is the "gain" of the discrete-time system and  φ(?) is the "phas

Why memory decoding is required, Why memory decoding is required? To a...

Why memory decoding is required? To attach a memory device to the microprocessor, this is necessary to decode the address sent by the microprocessor. Decoding creates the memo

Diod, explain the application of the Si,zener,and LED diodes

explain the application of the Si,zener,and LED diodes

Find the equivalent components of the network, Q. At the two terminals (A, ...

Q. At the two terminals (A, B) of a one-port network, the voltage and the current are given to be v(t) =200 √2 cos (377t + 60°) V and i(t) = 10√2 cos(377t + 30°) A. (a) Determin

Show the procedure twos complement subtraction, Q. Show the procedure twos ...

Q. Show the procedure twos complement subtraction? Two's complement subtraction is the binary addition of the minuend to the 2's complement of the subtrahend (adding a negative

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd