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Q. Show Equilibrium expression for water?
Ans.
The equilibrium expression for water is equal to a constant, Kw. This constant is called the ion product of water and is equal to 1.0 x 10-14:
Kw = [H+] [OH-] = 1.0 -> 10-14
There are two equilibrium constants, Ka and Kb, which are useful in describing the strength of acids and bases.
Suppose H-A and B-OH are an acid and base, respectively. Then Ka and Kb are defined as follows:
H-A -> H+ + A- Ka = [H+] [A-] / [H-A]
B-OH -> B+ + OH- Kb = [B+] [OH-] / [B-OH]
The higher Ka or Kb is, the greater the degree of ionization by the acid or base.
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Given the following mass percent compositions, determine the empirical formula: 49.5% C; 5.2% H; 28.8% N; 16.5% O.
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