Second quadrant or class b chopper, Electrical Engineering

Assignment Help:

Second Quadrant or Class B Chopper

Class B  chopper  is shown in figure in this  type of  chopper load  must contain  a dc source E ( may  be battery or a DC motor)  and inductances the  operation of classes B chopper as follows.

 Mode I

When SW  is on V0 = 0 but current will  be flowing  through  inductance L and  chopper SW  due to E as shown in figure in this mode inductance L stores energy.

Figure  shown the polarity of inductance  and direction of load  current.  It is clear  from this  figure that this  polarity's same as in directed but the  current is  flowing in reverse direction. Hence  is negative.

 Mode II

When SW  is off V0=  { E+ L  di0/dt}  exceeds the Vs  therefore  diode  D becomes forward  biased and current  flow   load to source  through diode D.  Again the load  voltage  is positive but current is in negative direction. In  this mode  inductance releases energy and the  polarity is shown in figure.

Hence  the Vo -I0  characteristics  is shown  in figure  that lie in second  quadrant.


Related Discussions:- Second quadrant or class b chopper

Switching characteristics during turn off, Switching Characteristics During...

Switching Characteristics During Turn off The techniques  used for turning off a thyristor is known  as  commutation techniques. A  thyristor can be can be  turn off by reducin

Can you explain about trapeziodal clippers, Q. Can you explain about Trapez...

Q. Can you explain about Trapeziodal Clippers? During The Positive half cycle, the diode D1 will be open circuited and the input appears as the output until, the applied bias v

What is open-loop voltage gain, Q. What is Open-loop voltage gain? The ...

Q. What is Open-loop voltage gain? The op amp amplifies the difference vd between the voltage on the noninverting (+) terminal and the inverting (-) terminal; see Figure. The t

Explain about differentiator, Q. Explain about Differentiator? Shown in...

Q. Explain about Differentiator? Shown in Figure is a differentiator which is obtained by replacing R1 in the inverting amplifier of Figure by a capacitor C. Assuming ideal op-

Induced emf, what is the difference between statically and dynamically indu...

what is the difference between statically and dynamically induced emf?

EMF, what is induced EMF & what is statically EMF explain in details.

what is induced EMF & what is statically EMF explain in details.

Evaluate the current using the loop-current method, Consider the circuit in...

Consider the circuit in Figure (a), which include a controlled source, and find the current in the 5-V source and the voltage across the 5- resistor by using (a) the loop-current

Magnetic Circuits:, A circular ring of magnetic material has a mean length ...

A circular ring of magnetic material has a mean length of 1m and a cross sectional area of .001m^2.A sawcut of 5mm width is made in the ring . calculate the magnetizing current req

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd