Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Second Quadrant or Class B Chopper
Class B chopper is shown in figure in this type of chopper load must contain a dc source E ( may be battery or a DC motor) and inductances the operation of classes B chopper as follows.
Mode I
When SW is on V0 = 0 but current will be flowing through inductance L and chopper SW due to E as shown in figure in this mode inductance L stores energy.
Figure shown the polarity of inductance and direction of load current. It is clear from this figure that this polarity's same as in directed but the current is flowing in reverse direction. Hence is negative.
Mode II
When SW is off V0= { E+ L di0/dt} exceeds the Vs therefore diode D becomes forward biased and current flow load to source through diode D. Again the load voltage is positive but current is in negative direction. In this mode inductance releases energy and the polarity is shown in figure.
Hence the Vo -I0 characteristics is shown in figure that lie in second quadrant.
Sketch the asymptotic Bode plot for
Peak inverse Voltage Peak inverse voltage is important parameter in the design of rectifier circuit. PIV is the maximum voltage that appears across the device during its
1. An analog information signal, whose maximum frequency is 6000Hz, is to be transmitted using a PCM system. The quantization error must not exceed the 1 % of the peak-to- peak an
Second Quadrant or Class B Chopper Class B chopper is shown in figure in this type of chopper load must contain a dc source E ( may be battery or a DC motor) and induct
One battery having of four cells, connected in series. Emf of each cell is 1.45V and internal resistance of 0.04Ω. if a load resistance of 5Ω is connected to the battery, draw the
What is ohmmeter An ohmmeter is an instrument for measuring resistance
Q. For a JKFFwith JK = 11, the output changes on every clock pulse. The change will be coincident with the clock pulse trailing edge and the flip-flop is said to toggle, when T = 1
how solving circuit by it
The following data apply to a 100-kW, 250-V, six-pole, 1000-r/min long-shunt compound generator: no-load rotational losses 4000 W, armature resistance at 75°C = 0.015 , series-fie
A 13.8 kV feed er circui t breaker has a 600:5 multira tio curr ent transform er with charact eristics as show n in Figure 5.11. Th e max - imum load on the feed er is 80 A pri mar
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd