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Q. Register-to-register operands in RISC?
Register-to-register operands: In RISC machines operation which access memories are LOAD and STORE. All other operands are kept in registers. This design feature make simpler the instruction set and consequently simplifies the CU. For illustrations a RISC instruction set can include only one or two ADD instructions (for example integer add and add with carry); on the other hand a CISC machine can have 25 add instructions including different addressing modes. Another advantage is that RISC encourages optimization of register use so that frequently used operands remain in registers.
What is the difference between top-down and bottom-up, programming? Ans: Top-down and Bottom-up Approaches In Top-down programming approach, we begin by identifying the main
Calculate the maximum access time that can be permitted for the data and control memories in a TSI switch with a single input and single output trunk multiplexing 2500 channels. Al
diagrams of picket fence problem
What is the necessity of Interfacing in digital ICs and what are the points to be kept in view, while interfacing between TTL gate and CMOS gate? Ans: To realize the optimum
Q. Illustarte Basic Flip-flops? Let's first see a ordinary latch. A latch or flip-flop can be created employing two NOR or NAND gates. Figure (a) presents logic diagram for S-R
Q. What is the working of domain expert? ANSWER: The domain expert is the person who gives the domain expertise in the form of problem-solving strategies.
Explain in detail companding. Companding: It is the process of compressing and expanding. This includes compressing the signal at the transmitter and expanding this at the re
Define a Gate Fix ASIC-based design in short. Gate Fix ASIC-based design: A Gate Fix implies that a select number of gates and their interconnections may be subtracted or ad
The Concept of Process Informally, a method is a program in execution, behind the program has been loaded in the main memory. However, a method is more than just a program code
How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB ? Ans. Here three product terms, therefore three AND gates of two inputs are needed.
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