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Q.Prove using Boolean Algebra
1. X (X+Y) = X
2. AB + AC + BC' = AC + BC'
3. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A
4. (A+B'+C) (AB+A'C) = (A+C) (A'+B)
5. XY + XZ + YZ' = XZ + YZ'
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Let us see the pairs that can be considered as adjacent in Karnaugh's here. The pairs are: 1) The four corners 2) The four 1's as in top and bottom in column 00 & 01
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if 2 forces are equal at an angle alpha between them - its resultant R and its direction
What is Race-around problem? How can you rectify this? The clock pulse which remains into the 1 state whereas both J and K are equal to 1 will reason the output to complement a
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