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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
5 2 ----- - ----- x-1 x+1 -------------------- x 1 ----- + ----- x-1 x+1
2+2=
what does 4/100+1/10=
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