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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
a mixture of 40 liters of milk and water contains 10% water.how much water should be added to this so that water my be 20% in the new mixture
Derivatives of Inverse Trig Functions : Now, we will look at the derivatives of the inverse trig functions. To derive the derivatives of inverse trig functions we'll required t
Integrals Involving Roots - Integration Techniques In this part we're going to look at an integration method that can be helpful for some integrals with roots in them. We hav
what is 15,909 in roman numeral
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Show that for odd positive integer to be a perfect square, it should be of the form 8k +1. Let a=2m+1 Ans: Squaring both sides we get a2 = 4m (m +1) + 1 ∴ product of two
the limit of f(x) as x approaches 5 is equal to 7. write the definition of limit as it applies to f at this point
Hierarchical Structures : As the abstractions from concrete objects and materials become more and more general, they represent wider and wider ideas. If we put down each step of
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Two trains leave two different cities 1,029 miles apart and head directly toward every other on parallel tracks. If one train is traveling at 45 miles per hour and the other at 53
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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