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(y+1/3x)^2
64n^2-1
what is the perpendicular line for y= -x= -3;(-2,-2)
In the earlier section we looked at using factoring & the square root property to solve out quadratic equations. The problem is that both of these methods will not always work. Not
if I have the equation 3(x+4y)+5(2x-y)an then I change it into (3x+12y)+(10x-5y) what property is it
The slope is -3 and the y-intercept is 4. How do I find a relation in the form y=mx+b which has a solution set line satisfying the given conditions?
Remember that a graph will have a y-intercept at the point (0, f (0)) . Though, in this case we have to ignore x = 0 and thus this graph will never cross the y-axis. It does get e
if im working out a problem that say 16 - t over 10 = -8 what be the answer
2xy^2 when x=3 and y=5
how would i solve one of these functions. like how would i find the domain and range? and may i get an example.
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