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x/4a^3 / 5x^3/6a^5x
using the formula for the difference between two squares,factor the following : 5-x
one no. is 7 more than another and its square is 77 more than the square of the smaller number.What are the numbers?
ac + xc + aw^2 +xw^2 i need to factor the problem above
Quadratic Formula It is the final method for solving quadratic equations & it will always work. Not only that, although if you can recall the formula it's a fairly simple proc
20
can any one help me with my geometry
Ask question #Minimum 100evaluate the expression log4 (x - 7) =3 words accepted#
x3+y3/x+y
a^4b+a^2b^3
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