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Optimization : In this section we will learn optimization problems. In optimization problems we will see for the largest value or the smallest value which a function can take.
In this section we will look at another kind of optimization problem. At this time we will be looking for the largest or smallest value of a function subject to some type of constraint. The constraint will be some condition (that can generally be defined by some equation) that has to absolutely, positively be true no matter what our solution is. On instance, the constraint will not be described easily by an equation, however in these problems it will be simple to deal with
Average cost function : Now let's turn our attention to the average cost function. If C ( x ) is the cost function for some of the item then the average cost function is,
THE CURVE C HAS POLAR EQUATION R=[X^1/2][E^X^2/PI]. WHERE X IS GREATER THAN OR EQUAL TO 0 BUT LESS THAN OR EQUAL TO PI. THE AREA OF THE FINITE REGION BOUNDED BY C AND THE LINE X EQ
70 multiply 67
ABCD is a trapezium AB parallel to DC prove square of AC - square of BCC= AB*
what is tan 45 degrees?
The quotient of 3d 3 and 9d 5 is The key word quotient means division so the problem becomes 1d 3 -5/ 5. Divide the coef?cients: 1d 3 /3d-5 . While dividing like bases, subt
find all the 8th roots of (19+7i)
Union and Intersection - Set theory B ∩ C indicates the intersection of B and C. it is the set having all those elements that belong to both B and C If B = {5, 8, 11, 20, 2
The math equation is written exactly this way: 0+50x1-60-60x0+10=??? The answer I get is 10 and others say 0 0+50=50 50x1=50 50-60=-10 -10-60=-70 -70x0=0 0+10=10
Find the least number that is divisible by all numbers between 1 and 10 (both inclusive). Ans: The required number is the LCM of 1,2,3,4,5,6,7,8,9,10 ∴ LCM = 2 × 2
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