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As noted earlier most parabolas are not given in that form. So, we have to take a look at how to graph a parabola which is in the general form.
Solve 2 x 10 - x 5 - 4 = 0 . Solution We can reduce this to quadratic in form using the substitution, u = x 5 u 2 = x 10 By using this substitution the equa
x2+4x-21
Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is. 1. Determine the vertex. We'll discus
6u+5>2
The length of a rectangle is twice it''s width. If the length of its diagonal is 16root5 cm, find its area
Now it is time to look at solving some more hard inequalities. In this section we will be solving (single) inequalities which involve polynomials of degree at least two. Or, to p
10000000004*56464684654654
need help on intro into algebra college homework
Linear Systems with Two Variables A linear system of two equations along with two variables is any system which can be written in the form. ax +b
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