Zeroes - roots of polynomials, Algebra

Assignment Help:

We'll begin this section by defining just what a root or zero of a polynomial is.  We say that x = r is a root or zero of a polynomial, P ( x) , if P ( r )= 0 .  In other terms x= r is a root or zero of a polynomial if it is a solution to the equation P ( x)= 0 .

In the next couple of sections we will have to find all the zeroes for a given polynomial.  thus, before we get into that we eh to get some ideas out of the way about zeroes of polynomials that will help us in that procedure.

The procedure of finding the zeros of P ( x ) really amount to nothing more than solving out the equation P ( x )= 0 and already we know how to do that for second degree (quadratic) polynomials.  Hence, to help illustrate some of the ideas were going to be looking at let's get the zeroes of a couple of second degree polynomials.

Let's first determine the zeroes for P ( x)=x2+ 2x -15 .  To do this simply we solve out the following equation.

x2+ 2 x -15 =( x + 5)(x - 3)= 0  ⇒  x = -5, x = 3

Thus, this second degree polynomial has two zeroes or roots.

Now, let's determine the zeroes for P ( x)= x2 -14 x + 49 . 

That will mean solving,

x2 -14x + 49 =( x - 7 )2= 0  ⇒  x = 7

Hence, this second degree polynomial contains a single zero or root. Also, remember that while we first looked at these we called a root like this a double root.

We solved out each of these by first factoring the polynomial and then by using the zero factor property onto the factored form.  While we first looked at the zero factor property we saw that it said that if the product of any two terms was zero then one of the terms had to be zero to begin with.

The zero factor property can be extended to as several terms as we need.  In other terms, if we've got a product of n terms i.e. equal to zero, then at least one of them had to be zero to start off with.  Thus, if we could factor higher degree polynomials then we could solve these as well.


Related Discussions:- Zeroes - roots of polynomials

Quadratic equation, If a firm sellings its product at a price $p per unit, ...

If a firm sellings its product at a price $p per unit, customers would buy q units per day where q = 1,350 - p. The cost of producing q units per day is $C(q) where C(q) = 50q + 36

Sum of cubes, x= sum of 2 perfect cubes in two ways

x= sum of 2 perfect cubes in two ways

Sail boating, How did they get an answer of 4.24899(-6) the question isc=4d...

How did they get an answer of 4.24899(-6) the question isc=4d(-1)/3.b. I now i substitute 23,245 for d and 13.5 for b, but don''t understand how they got this answer?

Complex fractions, how do I do complex fractions X over 25 over x over 15

how do I do complex fractions X over 25 over x over 15

Leading coefficient test, Assume that P ( x ) is a polynomial  along with d...

Assume that P ( x ) is a polynomial  along with degree n.  Thus we know that the polynomial have to look like,                                                     P ( x ) =ax n

Partial fractions, This section doesn't actually have many to do with the r...

This section doesn't actually have many to do with the rest of this chapter, but since the subject required to be covered and it was a fairly short chapter it appeared like as good

Multiply a row by a constant, Multiply a Row by a Constant.   In this opera...

Multiply a Row by a Constant.   In this operation we multiply row i by a constant c and the notation will utilizes here is cR i .  Note that we can also divide a row by a constant

Solve out the given system, Solve out the following system of equations by ...

Solve out the following system of equations by using augmented matrices. 3x - 3 y - 6 z = -3 2x - 2 y - 4 z = -2 -2x + 3 y + z = 7 Solution Notice that this system

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd