Zeroes - roots of polynomials, Algebra

Assignment Help:

We'll begin this section by defining just what a root or zero of a polynomial is.  We say that x = r is a root or zero of a polynomial, P ( x) , if P ( r )= 0 .  In other terms x= r is a root or zero of a polynomial if it is a solution to the equation P ( x)= 0 .

In the next couple of sections we will have to find all the zeroes for a given polynomial.  thus, before we get into that we eh to get some ideas out of the way about zeroes of polynomials that will help us in that procedure.

The procedure of finding the zeros of P ( x ) really amount to nothing more than solving out the equation P ( x )= 0 and already we know how to do that for second degree (quadratic) polynomials.  Hence, to help illustrate some of the ideas were going to be looking at let's get the zeroes of a couple of second degree polynomials.

Let's first determine the zeroes for P ( x)=x2+ 2x -15 .  To do this simply we solve out the following equation.

x2+ 2 x -15 =( x + 5)(x - 3)= 0  ⇒  x = -5, x = 3

Thus, this second degree polynomial has two zeroes or roots.

Now, let's determine the zeroes for P ( x)= x2 -14 x + 49 . 

That will mean solving,

x2 -14x + 49 =( x - 7 )2= 0  ⇒  x = 7

Hence, this second degree polynomial contains a single zero or root. Also, remember that while we first looked at these we called a root like this a double root.

We solved out each of these by first factoring the polynomial and then by using the zero factor property onto the factored form.  While we first looked at the zero factor property we saw that it said that if the product of any two terms was zero then one of the terms had to be zero to begin with.

The zero factor property can be extended to as several terms as we need.  In other terms, if we've got a product of n terms i.e. equal to zero, then at least one of them had to be zero to start off with.  Thus, if we could factor higher degree polynomials then we could solve these as well.


Related Discussions:- Zeroes - roots of polynomials

First form of the parabola, Let's go through first form of the parabola. ...

Let's go through first form of the parabola.                     f ( x ) = a ( x - h ) 2  + k There are two pieces of information regarding the parabola which we can instant

Differential Equations.., Differential Equations, Mathematics 1....

Differential Equations, Mathematics 1.Verify Liouville''''s formula for y "-y" - y'''' + y = 0 in (0, 1)

Kiera, how do you solve 9/x=4/12

how do you solve 9/x=4/12

Stephanie, a long distance telephone company charges 7 cents per minute or ...

a long distance telephone company charges 7 cents per minute or a 50 cent minimum charge per completed call, whichever is greater. Find the cost of a 1 minute call

Mathematical definition absolute value equations, We can also indicate a st...

We can also indicate a strict mathematical/formula definition for absolute value.  It is, It tells us to look at the sign of p & if it's positive we just drop the absolute

Literal equations and formulas, how do u solve the problem 2m=-6n-5 because...

how do u solve the problem 2m=-6n-5 because i tried everything and i cant get the answer?...

Vector algebra, #addition of vectors is associative

#addition of vectors is associative

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd