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One-to-one Correspondence : Suppose you are given a certain number of cups and saucers, and are asked to find out whether there are enough saucers for all the cups. How would you do this? By counting the number of cups and saucers, of course ! But what if you do not know how to count? Can you still answer the question? Yes, by matching (or pairing) each cup with a saucer. This means that you set up the cups and saucers in one-to-one correspondence with each other. Thus, pairing 'is simpler than counting, and is basic to it. You may have come across a situation similar to the following one, when interacting with preschoolers who are learning how to count.
A telephone dialled is numbered 0to9. if 0is dialled first the caller is connected to the international exchange system.find the number of local calls that can be rung if a local n
report on shares and dovidend using newspaer
Find the derivatives of the following functions a) y = 5x 4 +3x -1-x 3 b) y = (x+1) -1/2 c) y= e x2+1 d) y= e 3x lnx e) y =ln(x+1/x)y
prove that sin A /cot A + cosec A = 2 + sinA / cot A - cosec A
Perform the denoted operation for each of the following. (a) Add 6x 5 -10x 2 + x - 45 to 13x 2 - 9 x + 4 . (b) Subtract 5x 3 - 9 x 2 + x - 3 from x 2+ x +1.
pi to the ten-thousandths
1) A local factory makes sheets of plywood. Records are kept on the number of mild defects that occur on each sheet. Letting the random variable x represent the number of mild de
Two events A and B are independent events if the occurrence of event A is in no way related to the occurrence or non-occurrence of event B. Likewise for independent
Q. Find a common factor of the numerator and denominator? Ans. There's only one key step to simplifying (or reducing) fractions: find a common factor of the numerator and
A firm buys a product using the price schedule given in the table: The company estimate holding costs at 10% of the purchase price per year and ordering costs at $40 per order .
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