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Consider the equation
ex3 + x2 - x - 6 = 0, e > 0 (1)
1. Apply a naive regular perturbation of the form
do derive a three-term approximation to the solutions of (1).
2. The above perturbation expansion should only give you an approximation for 2 of the roots.
Apply a leading order balance argument to device suitable expansions for the other root, again in the limit e ! 0+. Again, derive a three-term approximation this third case.
3. Solve (1) numerically for e = 0.01 (use Matlab or Maple or something). Use your three-term approximation for the three roots found in Q1 and 2 and provide the error (in terms of a percentage) in each case.
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3 9/10 into decimal
Illustration: Find the solution to the subsequent IVP. ty' + 2y = t 2 - t + 1, y(1) = ½ Solution : Initially divide via the t to find the differential equation in
If Var(x) = 4, find Var (3x+8), where X is a random variable. Var (ax+b) = a 2 Var x Var (3x+8) = 3 2 Var x = 36
limit x APProaches infinity (1+1/x)x=e
need help with consumer surplus
How will you find the vertex of a parabola given in 2nd degree form (the axis of parabola is not parallel to coordinate axes)? Ans) Write the equation in type of standard form.
y=f(a^x) and f(sinx)=lnx find dy/dx Solution) dy/dx = (a^x)(lnx)f''(a^x), .........(1) but f(sinx) = lnx implies f(x) = ln(arcsinx) hence f''(x) = (1/arcsinx) (1/ ( ( 1-x
if ab=25 . a(5,x)and b(2,5) . find x.
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