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How will you find the vertex of a parabola given in 2nd degree form (the axis of parabola is not parallel to coordinate axes)?Ans)
Write the equation in type of standard form. Eg: (y-k)^2 = c(x-h)^2
That is making it a perfect square form.
The vertex is (h,k) in this format.
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Any point on parabola, (k 2 ,k) Perpendicular distance formula: D=(k-k 2 -1)/2 1/2 Differentiating and putting =0 1-2k=0 k=1/2 Therefore the point is (1/4, 1/2) D=3/(32 1/2
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